Riemann Sums
Approximating accumulation with rectangles · BC Calculus · greeting
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00:00End interview
f(x) on [1, 5]4 equal subintervalsΔx = 1Left / Right / MidΣ f(xᵢ*) Δx→ Riemann sumFiner partition → closer to the integral (usually)
Owl: You want the area under a smooth hill-shaped curve y = f(x) from x = 1 to x = 5, but you refuse to invent a fancy formula yet. Instead you draw four clumsy rectangles that roughly cover the region. Ugly? Yes. Useful? Extremely — because as the rectangles get thinner, the stacked areas usually settle toward a single number we will later call the definite integral. On the whiteboard, imagine partitioning [1, 5] into four equal pieces. Left endpoints, right endpoints, or midpoints each give a different stack. Which of those three sketches would you trust more for a first estimate — and why might "more rectangles" still not be exact?
You: